** Chapter 2 Linear Equations in One Variable Exercise 2.1**

Ex 2.1 Class 8 Maths Question 1.

Solve the equation: x – 2 = 7.

Solution:

Given: x – 2 = 7

⇒ x – 2 + 2 = 7 + 2 (adding 2 on both sides)

⇒ x = 9 (Required solution)

Ex 2.1 Class 8 Maths Question 2.

Solve the equation: y + 3 = 10.

Given: y + 3 = 10

⇒ y + 3 – 3 = 10 – 3 (subtracting 3 from each side)

⇒ y = 7 (Required solution)

Ex 2.1 Class 8 Maths Question 3.

Solve the equation: 6 = z + 2

Solution:

We have 6 = z + 2

⇒ 6 – 2 = z + 2 – 2 (subtracting 2 from each side)

⇒ 4 = z

Thus, z = 4 is the required solution.

Ex 2.1 Class 8 Maths Question 4.

Solve the equations:

Solution:

Ex 2.1 Class 8 Maths Question 5.

Solve the equation 6x = 12.

Solution:

We have 6x = 12

⇒ 6x ÷ 6 = 12 ÷ 6 (dividing each side by 6)

⇒ x = 2

Thus, x = 2 is the required solution.

Ex 2.1 Class 8 Maths Question 6.

Solve the equation

Solution:

Given

⇒

⇒ t = 50

Thus, t = 50 is the required solution.

Ex 2.1 Class 8 Maths Question 7.

Solve the equation

Solution:

We have

⇒

⇒ 2x = 54

⇒ 2x ÷ 2 = 54 ÷ 2 (dividing both sides by 2)

⇒ x = 27

Thus, x = 27 is the required solution.

Ex 2.1 Class 8 Maths Question 8.

Solve the equation 1.6 =

Solution:

Given: 1.6 =

⇒ 1.6 × 1.5 =

⇒ 2.40 = y

Thus, y = 2.40 is the required solution.

Ex 2.1 Class 8 Maths Question 9.

Solve the equation 7x – 9 = 16.

Solution:

We have 7x – 9 = 16

⇒ 7x – 9 + 9 = 16 + 9 (adding 9 to both sides)

⇒ 7x = 25

⇒ 7x ÷ 7 = 25 ÷ 7 (dividing both sides by 7)

⇒ x =

Thus, x =

Ex 2.1 Class 8 Maths Question 10.

Solve the equation 14y – 8 = 13.

Solution:

We have 14y – 8 = 13

⇒ 14y – 8 + 8 = 13 + 8 (adding 8 to both sides)

⇒ 14y = 21

⇒ 14y ÷ 14 = 21 ÷ 14 (dividing both sides by 14)

⇒ y =

⇒ y =

Thus, y =

Ex 2.1 Class 8 Maths Question 11.

Solve the equation 17 + 6p = 9.

Solution:

We have, 17 + 6p = 9

⇒ 17 – 17 + 6p = 9 – 17 (subtracting 17 from both sides)

⇒ 6p = -8

⇒ 6p ÷ 6 = -8 ÷ 6 (dividing both sides by 6)

⇒ p =

⇒ p =

Thus, p =

Ex 2.1 Class 8 Maths Question 12.

Solve the equation

Solution: